2y-8=y^2

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Solution for 2y-8=y^2 equation:



2y-8=y^2
We move all terms to the left:
2y-8-(y^2)=0
determiningTheFunctionDomain -y^2+2y-8=0
We add all the numbers together, and all the variables
-1y^2+2y-8=0
a = -1; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·(-1)·(-8)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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